php - Fatal error: Call to a function on a non-object in -

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I am printing information from a table (tblgroups) and after that I am using a group of members (TWG Group_member) avatars (Tblgroup_member)

When I try to get the Gram_id (I'm imprinting from the group) function Getmembers) This is telling me that I have a non-object ( $ memberinfo = $ Group- & gt; Getmembers ($ group ["group_id"]); ). But I declare the $ group = new group (); ?

It is saying that the mistake is on this line: $ memberinfo = $ group-> Getmembers ($ Group ["group_id"]);

PHP 

  $ group = new group (); Foreign exchange ($ group $ group) {resonant "& lt; p class = 'groupname' & gt; & lt; a href = 'group.php? Group_id =' $ group ['group_id']. '' & Gt; ". $ Group ['group_name']" & lt; / A & gt; & Lt; / P & gt; "; echo $ group ['group_id']; $ memberinfo = $ group- & gt; Getmembers ($ group [" group_id "]); / * Foreach ($ member $ $ as member) { Echo "& lt; P & gt; ". $ Member ['avatar']" & lt;

function gatemember (if necessary) 

  public function Getmembers ($ group_id) {$ db = New db (); $ Select = "SELECT g.group_id, m.user_id, u.avatar FROM ((tblgroups in G INNER tblgroup_member m g.group__id = m.group__id) INNER tblusers u include u.user_id = M.user_id) WHERE G Group_id = ". $ Group_id" "$ result = $ db -> Conn -> query ($ selection); $ Result_array = array (); while ($ line = mysqli_fetch_array ( $ Result)) {$ result_array [] = $ line;} return $ result_array;}

< P> Your first thing 

  $ group = new group ();

and then a loop 

  foreach ($ group $ group) {/ code>  
 you are inside the loop  
  
 
 here  $ group- & gt;  its This does not mean that the object is more than written in array data or other words from  foreach  and  $ group  is no longer an object 
 
  Solution  
 
 Changes 
   $ Group = New Group ();

to 

  $ group_obj = new group ();

then 

  $ memberinfo = $ group-> Getmembers ($ group ["group_id"]);

to 

  $ memberinfo = $ group_obj-> Getmembers ($ group ["group_id"]);

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