r - Replacement has more rows than data in for loop -

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First of all, I know that there is a question with a similar title, but it does not solve my problem.

I'm just trying to create a logarithmic stock price index with a log base 10 with loop like this: 

  t < - nrow [dat] dat $ logind & lt; - Matrix (NA, T, 1) Log in for $ 1 $ [1] & lt; - 100 (i in 2: t) {dat $ logind [i] & lt; - ($ $ logind [i-1] * (1 + dat $ logr [i]))}

dat is dataframe, logged in There is only one column that I have created, grab the index, and there are logarithmic returns in logger, however, it throws me down: 

  `$ & Lt; -. Data Error in frame` (`* TMP * ',' log '', value = C (100, 99.3891882,: 1155 rows in substitution, 1154 in data)

I have read that The error can be solved by using another method to select columns such as dat [, column] , but how to

[i] text "itemprop =" text ">

Instead of code> t <- nrow (dat) t <- nrow [dat] code> T because you are overtricating the function t (matrix / vector transfer).

For Loop using R-rated operators, such as: 

  $ longind  - c (100, $ $ logind [1: (nrow (dat ) -1)] * (1 + $ $ $ logr [-1]))

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