ajax - How to pass a view and a json from a function in laravel? -

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यह मेरा फ़ंक्शन है 

  अगर (isset ($ _ POST ['franchisesIds']) ) {$ Id_array = array (); विदेशी मुद्रा ($ _ POST ['फ्रैंचाइजीआईड्स'] $ डेटा के रूप में) {array_push ($ id_array, (int) $ डेटा ['id']); } $ परिणाम = डीबी :: तालिका ('फ्रेंचाइजी') - & gt; जहां में ('आईडी', $ id_array) - & gt; प्राप्त (); } वापसी प्रतिक्रिया :: जेएसन (सरणी ($ id_array)); वापसी देखें :: बनाने ('फ्रंटएण्ड। स्टोर्स') - & gt; साथ ('फ्रेंचाइजीज', $ परिणाम);

तो मैं इस सब डेटा को कैसे पारित करने के बारे में थोड़ा भ्रमित हूँ मुझे यकीन है कि सब कुछ काम करने के लिए सिर्फ json पास करने की आवश्यकता है और इसी समय मुझे देखने के लिए आईडी की एक सूची उत्तीर्ण करने की आवश्यकता है I मैं यह कैसे कर सकता हूं ??

उम्मीद है कि यह वही है जो आप चाहते थे: कृपया सीधे $ $ का उपयोग न करें _POST या $ _GET

<पूर्व> $ फ्रेंचाइजीज = आदान-प्रदान :: प्राप्त करें ('फ्रैंचाइजीआईड्स'); $ Id_array = array (); यदि ($ फ्रैंचाइजीआईडी) {विदेशी मुद्रा ($ फ्रैंचाइजीज $ डेटा के रूप में आयें) {array_push ($ id_array, (int) $ डेटा ['id']); } $ परिणाम = डीबी :: तालिका ('फ्रेंचाइजी') - & gt; जहां में ('आईडी', $ id_array) - & gt; प्राप्त (); } $ JsonArray = json_encode ($ id_array); वापसी देखें :: मेक ('फ्रंटएण्ड.स्टोरस') - & gt; साथ (अरै ('फ्रैंचाइजी सभी' = & gt; $ परिणाम, 'idArrays' = & gt; $ jsonArray));

दृश्य में कई मानों को पारित करने के लिए, कृपया इसके बारे में

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