c# 4.0 - Get value from json in c# -

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is the json string given below which is given to me as label Jason string

If you have any ideas, then share me .... 

  {"response": {"metinfo" : ["Timestamp": "2014-04-28T11: 55: 00.689 + 0000"}, "View": [{"Type": "Search displayed view tip", "Viewed": 0, "Result": [ Relevance ": 1.0," location ":" "" "dot", "name": "22.32963 73.24493", "display": {"latitude": 22.3296299, "longitude": 73.244923}, "map "" "{{" Latitude ": {" Latitude ": 22.3386231," Longitude ": 73.2352007}," Right below ": {" Latitude ": 22.3206367," Longitude ": 73.2546453}}," Address ": {" Additional Data 1.0, "district": 1.0, "distance": 32.4, "Milanleval": "", " "Location": "LINK_939680173_L", "Location type": "point", "display status": "location": {"country": 1.0, "state", "postal code": "location": {"location ID" ": {" Latitude ": 22.3296022," longitude ": 73.2452373}," map view ": {" left to left ": {" latitude ": 22.333 9 6," longitude ": 73 .24433}, "Right below": {"Latitude": 22.3287, "Longitude": 73.24571}}, "Address": `****` {label": "Harini," Vadodara "," Vadodara " "India", "State": "JJ", "County": "Vadodara", ",", "PostalCode": "India", "State": "India", "State": "Harinie", "Vadodara" : "{0}" "Additional Data": [{"Value": "India", "Key": "Country Name"}, {"Value": "Gujarat", "Key": "StateName"}]}}} }}}}}

download Jason DLL of Newtonsoft.

Then you can use JsonConvert.DeserializeObject or JsonConvert.SerializeObject

UPDATE: Here are instructions for installing it through NUG for Visual Studio

< P>

Here is an example of how to use it. 

  string json = @ "{'name': 'bad boys', 'release date': '1995-4-70000 00: 00', 'styles': ['action' 'Comedy']} "; Movie M = JsonConvert.DeserializeObject & lt; Movie & gt; (Json); String name = m.Name;

Just create an object for your JSON string (for each value) and then when you call deserializeObject, you referenced the label using MyObject.label Can


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